EC-313
Tuesday, November 20, 2012
Wednesday, October 17, 2012
HW: 10152012 (PART A)
Q1. PR-Corporation: $500 each unit, 6000 units/mth
Competitor: $450 each unit
Problem: Cuts PR-C's sale volume from 6000 to 4500
a. What is the arc price elasticity of demand between Potomac's oven and the competitor?
4500 - 6000 -1500 = $1050
4500 + 6000 = -$150 10500 = 0.1 ~ 1.00(arce)
$450 - $600
$450 +$600
b. Unit Elastic. Loss of sales may be a direct onsequence of decrease in consumer income.
c. -3.0 = 4500 - 6000
4500 + 6000 = X = 454.54
$X - $600
$X +$600
Q2. -2.2 = .20 * X --> .20 * -2.2 = -44 --> take absolute value of -44. This leads to a percentage increase in the quantity of computers sold will be 44%
Q3. 1800 - 1500
(1800 +1500)/2 = 300 * 2 = .001
2.25 - 1.75 .50 1650
(2.25 + 1.75)/2
Q7. 15 = (P) (1 + (1/1.2)) = 15 = (P)(.167) = 90, because 15/.167 equals 90 and 90 * .167 equals the
marginal revenue.
Q8.
Competitor: $450 each unit
Problem: Cuts PR-C's sale volume from 6000 to 4500
a. What is the arc price elasticity of demand between Potomac's oven and the competitor?
4500 - 6000 -1500 = $1050
4500 + 6000 = -$150 10500 = 0.1 ~ 1.00(arce)
$450 - $600
$450 +$600
b. Unit Elastic. Loss of sales may be a direct onsequence of decrease in consumer income.
c. -3.0 = 4500 - 6000
4500 + 6000 = X = 454.54
$X - $600
$X +$600
Q2. -2.2 = .20 * X --> .20 * -2.2 = -44 --> take absolute value of -44. This leads to a percentage increase in the quantity of computers sold will be 44%
Q3. 1800 - 1500
(1800 +1500)/2 = 300 * 2 = .001
2.25 - 1.75 .50 1650
(2.25 + 1.75)/2
Q7. 15 = (P) (1 + (1/1.2)) = 15 = (P)(.167) = 90, because 15/.167 equals 90 and 90 * .167 equals the
marginal revenue.
Q8.
Monday, September 24, 2012
HomeWork 092412
Managerial Homework
Complete the following:
I.
Investment 1 Investment 2
rj pj rj pj
-100 .05 -1000 .01
0 .05 -500 .05
100 .05 0 .53
200 .80 500 .40
300 .05 1000 .01
Find 𝑟 for both investments
Investment1: (-100*.05) + (0*.05) + (100*.05) + (200*.80) +(300*.05) = 175
Investment2:(-1000*.01) + (-500*.05) + (0*.53) + (500*.40) + (1000*.01) = 175
Find σ for both investments
Invest.1: SQRT( (-100-175)^2 + (0-175)^2 + (100-175)^2 + (200-175)^2 +(300-175)^2) = 80.039
Invest.2: SQRT( (-1000-175)^2 + (-500-175)^2 + (0-175)^2 + (500-175)^2 +(1000-175)^2) = 319.2
I1. 175/80.039= 2.18 ** more risky
I2. 175/319.18=.55
II.
Assume you face an investment such that 𝑟=1000 and σ=300
What is the probability that this investment makes less than 0? 300? 1000? 1500?
1. 0-1000/300 ---> -3.33; P = .0004
2. 300-1000/300----> 2.33; P = .9901
3. 1000-1000/300---> 0; P = .5000
4. 1500-1000/300---> 1.64; P = .9495
Complete the following:
I.
Investment 1 Investment 2
rj pj rj pj
-100 .05 -1000 .01
0 .05 -500 .05
100 .05 0 .53
200 .80 500 .40
300 .05 1000 .01
Find 𝑟 for both investments
Investment1: (-100*.05) + (0*.05) + (100*.05) + (200*.80) +(300*.05) = 175
Investment2:(-1000*.01) + (-500*.05) + (0*.53) + (500*.40) + (1000*.01) = 175
Find σ for both investments
Invest.1: SQRT( (-100-175)^2 + (0-175)^2 + (100-175)^2 + (200-175)^2 +(300-175)^2) = 80.039
Invest.2: SQRT( (-1000-175)^2 + (-500-175)^2 + (0-175)^2 + (500-175)^2 +(1000-175)^2) = 319.2
I1. 175/80.039= 2.18 ** more risky
I2. 175/319.18=.55
II.
Assume you face an investment such that 𝑟=1000 and σ=300
What is the probability that this investment makes less than 0? 300? 1000? 1500?
1. 0-1000/300 ---> -3.33; P = .0004
2. 300-1000/300----> 2.33; P = .9901
3. 1000-1000/300---> 0; P = .5000
4. 1500-1000/300---> 1.64; P = .9495
Monday, September 10, 2012
Homework 091012
Problem 1:
Total Cost: 300 + 75q + 5q^2
Price: 825 - 20q
#1. Profit = (825 -20q) q - 300 - 75q - 10q
P = 825Q - 20Q^2 - 75 - 10Q
P = 825 - 40Q - 75 - 10Q
P = 750 - 30q
#2. Thus,
dTR = 750/30q = 25q**
dQ
#3. Price: 825 - 20(25) = 325
Min: 25; Max: 30
#4. TR= (825 - 20(25)) (25)
= 325 * 25
= 8 ,125
#5. TC= 75Q + 5Q^2
= 75(25) + 10(25)
= 2,125
#6. Profit =6000
Problem 2:
TC = 34 + 80Q + 12Q^2
P = 160 + 2Q
Profit =160q + 2q^2 - 34 - 80q- 24q
P= 160q + 4q - 80q -24q
P = 80 - 20q (1st "D")
Thus,
dTR= 80-20q = 4
dQ
Price= P = 160 + 2(4) = 168
Min: 4; Max: 20
TR= (160 + 2(4)) (4) = 672
TC = 80(4) +24(4) = 416
Profit = 256
Total Cost: 300 + 75q + 5q^2
Price: 825 - 20q
#1. Profit = (825 -20q) q - 300 - 75q - 10q
P = 825Q - 20Q^2 - 75 - 10Q
P = 825 - 40Q - 75 - 10Q
P = 750 - 30q
#2. Thus,
dTR = 750/30q = 25q**
dQ
#3. Price: 825 - 20(25) = 325
Min: 25; Max: 30
#4. TR= (825 - 20(25)) (25)
= 325 * 25
= 8 ,125
#5. TC= 75Q + 5Q^2
= 75(25) + 10(25)
= 2,125
#6. Profit =6000
Problem 2:
TC = 34 + 80Q + 12Q^2
P = 160 + 2Q
Profit =160q + 2q^2 - 34 - 80q- 24q
P= 160q + 4q - 80q -24q
P = 80 - 20q (1st "D")
Thus,
dTR= 80-20q = 4
dQ
Price= P = 160 + 2(4) = 168
Min: 4; Max: 20
TR= (160 + 2(4)) (4) = 672
TC = 80(4) +24(4) = 416
Profit = 256
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